Question

The distance of point(2,-3) from the line 6x-8y-1=0 is?​

Answer 1

Answer:

Now the distance of the point (3,4) from the line 6x+8y=5 is

=

∣

∣

∣

∣

∣

6

2

+8

2

6.3+4.8−5

∣

∣

∣

∣

∣

=

∣

∣

∣

∣

∣

100

45

∣

∣

∣

∣

∣

=

10

45

=

2

9

.