Question

the distance of point (4;7) from y axis is​

Answer 1

Answer:

4 Units

Step-by-step explanation:

Given is the point (4,7)

Let the point be X (4,7)

We have to find the distance between the point X from the y-axis.

Let the point on the y-axis be Y.

The point on the y-axis be Y(0,7)

∴ The distance between X and Y will be $D =  \sqrt{(X2-X1)^{2} + (Y2-Y1)^{2}  }$

$D =  \sqrt{(4-0)^{2} + (7-7)^{2}  }$

$D =  \sqrt{(4)^{2} + (0)^{2}  }$

$D = \sqrt{16}$

∴ D = 4 units

∴ The distance between the two point is 4 units