Question

The distance of the field point on axis of a small electric dipole is doubled . By what factor will the electric field due to dipole charge ?

Answer 1

for a short dipole,
electric field at an axial position is inversely proportional to the third power of distance b/w the centre of dipole and the point!!!

so, if the distance is doubled, electric field will reduce with a factor of 1/8 th times.

Answer 2

Answer:

1 / 8

Explanation:

For small dipole,

$\mathrm{E}_{\text {axis }}=\frac{1}{4 \pi \epsilon_{0}} \frac{2 \mathrm{p}}{\mathrm{r}_{3}} \propto \frac{1}{\mathrm{r}^{3}}$

When $\mathrm{r}$ is doubled, the electric field strength become 1 / 8 times of the original field.

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