Question

The distance of the planet Jupiter from the Sun is 5.2 times that of the
Earth. Find the period of Jupiter’s revolution around the Sun.

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Answer 1

$\begin {gathered} {\underline {\blue {\boxed{\sf{Answer}}}}} \end {gathered}$

➡$we \: know \: that \: {t}^{2} \ infinite {r}^{2}$

➡$\frac{t \frac{2}{j} }{t \frac{2}{e} } = \frac{r \frac{3}{j} }{ r \frac{3}{e} }$

➡$t \frac{2}{j} = \frac{t \frac{2}{e} {(5.2 r_{e} }^{3} )}{r \frac{3}{e} }$

➡$140.6t \frac{2}{e}$

➡$t_ {j} = 11.86 t_{e}$

➡$where \: \: t_{e} \: \: is \: \: the \: \: time \: \: period \: \: of \: \: earth.$

please scroll to right ➡➡ slightly to get your answer.