Question

the distance of the point (2,11) from x axis will be ?
​

Answer 1

given,

(x,y)=(2,11)

at x axis y=0

so, x1,y1=(a,0)

therefore, the distance of the point (2,11) from the x axis is

√[(x-x1)+(y-y1)]

√[(2-a)+(11-0)]

√(4-4a+a²+11²)

√(4-4a+a²+121)

√a²-4a+125