Question

The distance of the point (-2,-2) from the origin is

Answer 1

GIVEN :

The distance of the point (-2, -2) from the origin (0,0) :

TO FIND :

The distance of the point (-2, -2) from the origin (0,0).

SOLUTION :

Given that the two points are (-2,-2) from the origin.

ie., The points are (-2,-2) and (0,0)

Let  $(x_1,y_1)$ and $(x_2,y_2)$ be the given points (-2,-2) and (0,0) respectively.

The formula for distance between the given two points is :

$s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ units

Substituting the values in the distance formula we get,

$s=\sqrt{(0-(-2))^2+(0-(-2))^2}$ units

$=\sqrt{(0+2)^2+(0+2)^2}$ units

$=\sqrt{2^2+2^2}$

$\sqrt[4+4}$$=\sqrt{4+4}$

$=\sqrt{8}$

$s=2\sqrt{2}$ units

⇒ $s=\sqrt{8}$ units or $s=2\sqrt{2}$ units

∴ the distance between the point (-2,-2) from the origin (0,0) is $s=\sqrt{8}$ units or $s=2\sqrt{2}$ units

Answer 2

Answer:

GIVEN :

The distance of the point (-2, -2) from the origin (0,0) :

TO FIND :

The distance of the point (-2, -2) from the origin (0,0).

SOLUTION :

Given that the two points are (-2,-2) from the origin.

ie., The points are (-2,-2) and (0,0)

Let  (x_1,y_1)(x1,y1) and (x_2,y_2)(x2,y2) be the given points (-2,-2) and (0,0) respectively.

The formula for distance between the given two points is :

s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}s=(x2−x1)2+(y2−y1)2 units

Substituting the values in the distance formula we get,

s=\sqrt{(0-(-2))^2+(0-(-2))^2}s=(0−(−2))2+(0−(−2))2 units

=\sqrt{(0+2)^2+(0+2)^2}=(0+2)2+(0+2)2 units

=\sqrt{2^2+2^2}=22+22

\sqrt[4+4} =\sqrt{4+4}=4+4

=\sqrt{8}=8

s=2\sqrt{2}s=22 units

⇒ s=\sqrt{8}s=8 units or s=2\sqrt{2}s=22 units

∴ the distance between the point (-2,-2) from the origin (0,0) is s=\sqrt{8}s=8 units or s=2\sqrt{2}s=22 units