The distance of the point - 2, 3 from x axis is 5 find the coordinates of the point on x-axis
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Answer:
=√(x2 -x1)^2 + (y2-y1)^2
5=√x2+2)^2+(y2-3)^2
25 = x^2+2+2x +y^2+2+2y
25 = x^2+2x+4+y^2+2y
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