Question

The distance of the point ( 3, 4 ) from -axis is

A) 3 units B) 4 units

C) 5 D) 7 units​

Answer 1

Distance = √(3)² + (4)²

= √9+16 = √25 = 5 units

Answer 2

c) 5 units .

x₁ = 0 ; y₁ = 0

x₂ = 3 ; y₂ = 4

Distance :-

$\sf{\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}}\\\\ = \sf{\sqrt{(3-0)^2 + (4-0)^2}} \\\\ = \sf{\sqrt{(3)^2+(4)^2}} \\\\ = \sf{\sqrt{9+16}} \\\\ = \sf{\sqrt{25}} = 5~units$