Question

The distance of the point A(11, 12) from the Y-axis is 13 unit. Find co-ordinates of this point.​

Answer 1

hey mate here is your ans it’s in the attachment

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Answer 2

Answer:

     $12+4\sqrt{3}, 12-4\sqrt{3}$ are our points.

Step-by-step explanation:

The distance between two points is the length of the line connecting the two points. If two points lie on the same horizontal or the same vertical line, the distance can be found by subtracting the coordinates that are not the same.

In analytic geometry, the distance formula is used to find the measure of the distance between two line segments, the sum of the lengths of all sides of a polygon.

The distance between two points in the XY plane can be found using the distance formula. The ordered pair (x, y) represents the coordinate of a point, where the x-coordinate (or abscissa) is the point's distance from the x-axis and the y-coordinate (or y) is the point's distance from the y-axis.

The distance between parallel lines is the shortest distance from any point on one of the lines to the other line.

Also defined as, Distance between two parallel lines = Perpendicular distance between them.

Consider two parallel lines, y = mx + $c_{1}$ and y = mx + $c_{2}$

According to the question

Let the coordinates of the point be (x,y)

Since the point from the y-axis is 13 units hence x-coordinate of this point is 0

Hence our coordinates will be (0,y)

Now applying distance formulae between the point and A(11,12)

$\sqrt{(y-12)^2+(11-0)^2}=13\\ (y-12)^2+11^2=169\\y^2+144-24y=48\\y^2-24y+96=0$

On solving for y we get values of y as: $12+4\sqrt{3}, 12-4\sqrt{3}$

Hence      $12+4\sqrt{3}, 12-4\sqrt{3}$ are our points.

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