Question

The distance of the point A (-2,-5) from the Y-axis (in Units )is
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Answer 1

Step-by-step explanation:

Let B(0 - 5) be the point present on y-axis.

$\therefore \: d(AB) = \sqrt{( - 2 - 0)^{2} + \{ - 5 - ( - 5)\}^{2} } \\ \\ \therefore \: d(AB) = \sqrt{( - 2)^{2} + \{ - 5 + 5\}^{2} } \\ \\\therefore \: d(AB) = \sqrt{( - 2)^{2} + \{0\}^{2} } \\ \\ \therefore \: d(AB) = \sqrt{4 + 0 } \\ \\ \therefore \: d(AB) = \sqrt{4 } \\ \\ \therefore \: d(AB) = 2 \: units.$

Therefore, distance of the point A (-2,-5) from the Y-axis is 2 units.

Answer 2

The distance of point A(-2,-5) from Y axis =1

Step-by-step explanation:

Given :A(-2,-5)

To Find : The distance of the point A (-2,-5) from the Y-axis (in Units )is

Solution :

x = -2 , y = -5

x represents the the distance of point form y axis

y represents the the distance of point form x axis

So, The distance of point A(-2,-5) from Y axis =2

#Learn more:

Write the distance of the point (-5,4)from x-axis

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