Question

The distance of the point A(7,2 ) from Y-axis is
a) 7 units (b) 2 units (c) 9 units (d) 5 units​

Answer 1

The distance of the point A(7, 2) from Y-axis is 2

Answer 2

The distance of the point A(7,2) from y-axis is 7 units [Option (a)].

Step-by-step explanation:

We have to find the distance of the point A(7,2) from y-axis, which means that we have to find the distance between points A(7,2) and (0,2).

Let the other point be B, i.e., B(0,2).

$\because$ The dist. between any 2 pts $A (x_{1},y_{1})\ \& \ B (x_{2}{,y_{2})$ =$\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

                  So, distance between A(7,2) and B(0,2)  = $\sqrt{(0-7)^{2}+(2-2)^{2}}$

                                                                                      = $\sqrt{(-7)^{2}+(0)^{2}}$

                                                                                      = $\sqrt{49+0}$

                                                                                      = $\sqrt{49}$

                                                                                      = 7 units.

                                                                           (As distance is always positive)

Thus, the distance between A(7,2) and y-axis is 7 units.