Math, asked by snikhila85, 3 months ago

The distance of the point
(b cos theta,b sin theta)
from origin is

Answers

Answered by yogeshchouhan211
3

Answer:

By distance formula

2a cos Q

Attachments:
Answered by CopyThat
11

→Question: The distance of the point  (b cos theta,b sin theta)  from origin is:

→Answer: To find distance, we use the distance formula:

⇒Distance formula: √(x2 - x1)² - (y2 - y1)²

⇒Where:

  • x2 = bcosθ
  • x1  = 0
  • y2 = bsinθ
  • y1  = 0

⇒Now:

  • √(bcosθ - 0)² + (bsinθ - 0)²
  • √b²cos²θ + b²sin²θ
  • √b²(cos²θ + sin²θ)
  • b√1
  • b

⇒ x and y coordinates:

⇒        (0,0)   A______________________________B (bcosθ,bsinθ)

∴The distance between the point bcosθ , bsinθ from the origin is b.


Anonymous: tq~ good
THankrrrrrr: yeahh
Similar questions