The distance of the point
(b cos theta,b sin theta)
from origin is
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3
Answer:
By distance formula
2a cos Q
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→Question: The distance of the point (b cos theta,b sin theta) from origin is:
→Answer: To find distance, we use the distance formula:
⇒Distance formula: √(x2 - x1)² - (y2 - y1)²
⇒Where:
- x2 = bcosθ
- x1 = 0
- y2 = bsinθ
- y1 = 0
⇒Now:
- √(bcosθ - 0)² + (bsinθ - 0)²
- √b²cos²θ + b²sin²θ
- √b²(cos²θ + sin²θ)
- b√1
- b
⇒ x and y coordinates:
⇒ (0,0) A______________________________B (bcosθ,bsinθ)
∴The distance between the point bcosθ , bsinθ from the origin is b.
Anonymous:
tq~ good
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