The distance of the point P(-3,-4) from the x axis is.....???
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Answered by
3
Answer:
0,0
Step-by-step explanation:
According to your theorem
Here x2=0,x1=-3,y2=0,y1=-4
then line ofthe distance formula PQ=[(x2-xq)sq.+(y2-y1)sq.]
PQ=9+16
PQ=25
Answered by
2
The Answer is in the above attachment
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