Question

The distance of the point p(3, -5) from x-axis is

Answer 1

Answer:

distance = √{(3-x)²+(-5-0)²} = √{9+x²-6x+25}

= √{x²-6x+34}

Answer 2

Answer:

the distance from x axis 5 units

as the point is 5 units above the x axis (which is the y coordinate and it cannot

                                                                   be negative as it is distance)

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