Question

The distance of the point p(5,-1) from y axis is

Answer 1

Step-by-step explanation:

y= -1

because we say x axis then y axis

so -1is after y

Answer 2

The distance of the point p(5,-1) from y axis is 5 units.

Step-by-step explanation:

We have to find the distance of point p(5,-1) from y axis.

Equation of y-axis:

$x = 0$

Formula used:

$\text{Distance}(ax+by+c=0,(x_0,y_0)) = \bigg|\dfrac{ax_0+by_0+c}{\sqrt{a^2+b^2}}\bigg|$

Comparing, we get,

a = 1

b = 0

c = 0

Distance =

$D = (x=0,(5,-1)) = \bigg|\dfrac{1(5)+(0)(-1)+(0)}{\sqrt{(1)^2+(0)^2}}\bigg|\\\\D = 5$

The distance of the point p(5,-1) from y axis is 5 units.

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