Question

The distance of the point p(-6 8) from the origin is

Answer 1

Answer:

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Answer 2

The distance of the point p(-6,8) from the origin is 10 units.

Step-by-step explanation:

Since we have given that

Distance of the point p(-6,8) from the origin.

So, coordinates of origin is (0,0)

As we know that

Distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So, it becomes,

$Distance=\sqrt{0-(-6))^2+(0-8)^2}\\\\Distance=\sqrt{6^2+8^2}\\\\Distance=\sqrt{36+64}\\\\Distance=\sqrt{100}\\\\Distance=10\ units$

Hence, the distance of the point p(-6,8) from the origin is 10 units.

# learn more:

Find the distance of the point p (-6, 8) from the origin

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