Question

The distance of the point P (6,-8) from the origin is
(a) 8 units 1) 217 units for 10 units
(d) 6 units
units​

Answer 1

Answer:

the distance of the point P(6,-8) from the origin (0,0) is 10 units.

Answer 2

Solution :-

Distance of the points P(6, - 8) from the origin d = √(x² + y²)

Here

P(6, - 8)

→ x = 6

→ y = - 8

Substituting the values

$\implies d = \sqrt{ {6}^{2} + {( - 8)}^{2} }$

$\implies d = \sqrt{ 36 + 64 }$

$\implies d = \sqrt{100}$

$\implies d = 10$

Hence, distance of the point P (6,-8) from the origin is 10 units.