Question

the distance of the point
$( - 3 4) from \: the \: x - axis \: is$

Answer 1

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3--wife ku thali katuvanga
4--lover ku Ena katuvanga?

Answer : 6letter
_ R_B_U

Small tips
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Answer 2

Let the point on the x axis be (x,0)

Obvoiusly the point will be (-3,0) which is the shortest distance from (-3,4)  to the x-axis.

Now we know that :

By Distance formula distance between A (x1,y1) and B(x2,y2) is:

$\sqrt{(x2-x1)^2+(y2-y1)^2}$

Given:

points are:

(-3,4)

(-3,0)

x1 , y1 = -3 , 4

x2 , y2 = -3 ,0

$\implies \sqrt{(-3+3)^2+(0-4)^2}$

$\implies \sqrt{0^2+(-4)^2}$

$\implies \sqrt{16}$

$\implies \pm 4$

Distance cannot be negative .

So d = 4 units

The distance of the point from the x axis is 4 units.

Hope it helps you

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