Question

The distance of the points (5, 0) and (–3, 0) from x-axis is:

Answer 1

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by the distance formula.

$\sqrt{(x2 - x1) ^{2} +(y2 - y1)^{2} }$

so the points are A(5,0) and B(-3,0)

now

$AB = \sqrt{( - 3 - 5)^{2} + (0 - 0) ^{2} }$

$AB = \sqrt{ {(8)}^{2} - 0 } \\ AB = 8cm$

hope it help ❣

Answer 2

Answer:

It will be 2 i.e. 5+ (-3)

= 5-3 which is 2.