The distance of the ship from the base of the light house when angle of depression is 30". is: Co) 30/3 m (b) 10
m 1.0 3 m (c) 30 m () ir
Answers
Answered by
0
Answer:
BAC=90−60
o
=30
o
Thus, ∠A=30
o
tan30
o
=
AB
BC
3
1
=
30
x
x=
3
30
×
3
x=10
3
m
Answered by
0
Answer:
Let, the height of lighthouse from sea level (AB)=100m
Let, two ships are at the positions be C and D
In △ABC,
tan 45
∘
=
BC
AB
⟹1=
BC
100
⟹BC=100m
In △ABD,
tan 30
∘
=
BD
AB
⟹
3
1
=
BD
AB
BD=AB×
3
=100×
3
=173.2[
3
=1.732]
∴CD=BD−BC=173.2=100=73.2m
∴ the distance between two ships 73.2 m
Step-by-step explanation:
Similar questions