Question

The distance of the straight line from the origin is 6 and angle made by the normal from the origin to the line with the positive direction of x-axis is 150 degrees , then the equation of the straight line is
a) \sqrt{3}-y+12=0
b) x-\sqrt{3}y+12=0
c) \sqrt{3}y-x+12=0
d) \sqrt{3}x-y-12=0

Answer 1

Step-by-step explanation:

The distance of the straight line from the origin is 6 and angle made by the normal from the origin to the line with the positive direction of x-axis is 150 degrees , then the equation of the straight line is

a) \sqrt{3}-y+12=0

b) x-\sqrt{3}y+12=0

c) \sqrt{3}y-x+12=0

d) \sqrt{3}x-y-12=0

i think option 1 is the correct answer....

hey mark it as the brainliest