Math, asked by laasyasbodh2000, 7 months ago

the distance of tje point p(6,-6) from the origin ​

Answers

Answered by Anonymous
0

Distance from origin=√x²+y²=√36+36=6√2units.

........

............

Answered by Anonymous
21

Answer:

Given:-

Pc,y)=P(6,-6)

Formula used:-

P(x,y)=√x²+y²

  • x=6

  • y=-6

substitute in Formula:-

=>P(x,y)=x²+

=>P(x,y)=(6)²+(-6)²=36+36=72

Similar questions