the distance of tje point p(6,-6) from the origin
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Answered by
0
Distance from origin=√x²+y²=√36+36=6√2units.
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Answered by
21
Answer:
Given:-
Pc,y)=P(6,-6)
Formula used:-
P(x,y)=√x²+y²
- x=6
- y=-6
substitute in Formula:-
=>P(x,y)=√x²+y²
=>P(x,y)=√(6)²+(-6)²=√36+36=√72
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