Question

the distance S along x axis varies with time as S = 2t^3 + 3t^2 + 6t + 2 . Find t at acceleration becomes zero

Answer 1

Answer: 0.5 sec

Explanation: v=ds/dt

S is already given so when you put the value of s and then deferentiate then you will get

V=6t^2+6t+6.

Since

A=dv/dt

Putting value of v and then differentiating it you will get

A=12t+6 (eq.1)

We know that when body is in rest its acceleration is 0.

So putting a=0 in eq.1 we get

0=12t+6

-6/12=t

T= -1/2

Since time is never in -ve

T = 0.5sec

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