the distance s km traveled by a train in t hours is given by s= t^3+3t^2+t-6. find the velocity & acceleration at the end of 3 hours
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Answer:
velocity = 17 km / hour
Step-by-step explanation:
given
S = t3 + 3t2 + t- 6
t = 3
S= 3×3×3 + 3×3×3 + 3 - 6
S = 51 km
V = S /T
V = 51 / 3
V = 17 km / hour
acceleration is same as velocoty if initial velocity is zero
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