Math, asked by pranaviswethas, 3 months ago

The distance - time graph of a particle in a projectile motion is a curve, parabola. When a body
it followed is a parabola and parabolas are symmetric. The general equation of a parabola is y=
projected from the ground, it reaches a certain height and comes back to the ground. The path why
MA
x(Quadratic polynomial)
1)
If the projected parabolic path is represented by the equation y=12-7t + 12 then what are the zero
a) (-1,5)
d) (-4.-3) D
b) (4.3)
c)(-2,3)
ii)
If the body is in ground level at t = 4 sec and t = 7 sec, then the representation of the projectile is
a) t2 - 5t + 3
b) 2 - 14 t + 11 6) 2 - 111 +28 d) t-28 t + 111
The representation of the projectile whose one root is -5 and the other root is its reciprocal is
a) 2 + 25
b) t- 25
c) ² + √5
d) - √
[
iv)
Consider the projectile is represented as t2 - 9 + 20. If the body is projected 2 sec later than the actu
s time and reaches the ground 2 sec later than the actual time. The representaion of the projectile is
a) +-15t + 30 b) 2 - 18t +42 c)+ 18t - 42 d) 1 - 420
V)
If one of the root of the projectile is 2 + 13, then the other is
a) 3+3
b)
c) 5+ V2
d) 0
2+√3​

Answers

Answered by calebmdavis9
1

Answer:

The general equation of a parabola is y= projected from the ground, it reaches a certain height and comes back to the ground.

If the projected parabolic path is represented by the equation y=12-7t + 12 then what are the zero

a) (-1,5)

d) (-4.-3) D

b) (4.3)

c)(-2,3)

ii)

If the body is in ground level at t = 4 sec and t = 7 sec, then the representation of the projectile is

a) t2 - 5t + 3

b) 2 - 14 t + 11 6) 2 - 111 +28 d) t-28 t + 111

The representation of the projectile whose one root is -5 and the other root is its reciprocal is

a) 2 + 25

b) t- 25

c) ² + √5

d) - √

[

iv)

Consider the projectile is represented as t2 - 9 + 20. If the body is projected 2 sec later than the actu

s time and reaches the ground 2 sec later than the actual time. The representaion of the projectile is

a) +-15t + 30 b) 2 - 18t +42 c)+ 18t - 42 d) 1 - 420

V)

If one of the root of the projectile is 2 + 13, then the other is

a) 3+3

b)

c) 5+ V2

d) 0

2+√3​

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