Question

The distance - time graph of an object is given below.

() In which interval, the object was at rest ?

() What is the acceleration during the interval 0 to 1 ?

() Do the object return to the initial position ? Why ?

() What is the average velocity of the overall trip ?​

Answer 1

Step-by-step explanation:

So to find the position of the object at time 20 second, we draw a line parallel to y-axis from time 20 and take the point where it intersects then again draw a line parallel to the x-axis, we get the distance where it intersects the y-axis.

Here the position is 8 meters from starting.

ii) Distance travel in 12 seconds by the object is 6 meters.

iii) Since average speed of object is define as total distance covered by object by total time take. So here total distance is 8 m and the total time is 20 second,

Average speed =

= 0.4 m/s

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