Question

The distance traveled by a body before coming to rest if it is moving on rough surface with a velocity 36kmph and the coefficient of friction between the body and the surface is 0.2 is​

Answer 1

Answer:25m

Explanation:Use work kinetic energy theorem

Answer 2

Answer:

The distance traveled by a body before coming to rest if it is moving on a rough surface with a velocity of 36km/h and the coefficient of friction between the body and the surface is 0.2 is​ $25.5m$

Explanation:

When a body is moving on a frictional surface it travels a distance before it comes to rest, this distance is named as stopping distance

for a body moving with velocity $v$ on a frictional surface with a coefficient of friction μ the stopping distance is given by the formula

$d=\frac{v^2}{2\mu g}$

where the acceleration due to gravity $g=9.8m/s^{2}$

from the question, we have

the velocity of the body $v=36km/h=36*5/18m/s=10m/s$

the coefficient of friction μ$=0.2$

substitute the given values to get the distance traveled before it comes to rest

$d=\frac{10^{2} }{2*0.2*9.8}=25.5m$