Question

The distance travelled by a body during last
second of its upward journey is 'd', when the
body is projected with certain velocity vertically
up. If the velocity of projection is doubled, the
distance travelled by the body during the last
second of its upward journey is​

Answer 1

Answer:

Same = d

Explanation:

The distance travelled by a body during last

second of its upward journey is 'd', when the

body is projected with certain velocity vertically

up. If the velocity of projection is doubled, the

distance travelled by the body during the last

second of its upward journey is​

Let say Velocity = V

Velocity at Peak = 0

time taken to reach at peak = T

0 = V - gT

=> T = V/g

Velocity at T - 1 Sec = V - g(T-1) = V - g(V/g - 1)  = V - V + g = g m/s

Distance covered in Last sec using V² - U² = 2aS

=> 0² - g² = 2(-g)d

=> d = g/2

Now Velocity = 2V

=> T = 2V/G

Velocity at T - 1 Sec = 2V - g(T-1) = 2V - g(2V/g - 1)  = 2V - 2V + g = g m/s

=> 0² - g² = 2(-g)s

=> s = g/2

=> s = d

distance traveled by the body during the last  second of its upward journey is​ same d

Answer 2

Answer:

Explanation:

Hope it will help you guys