the distance travelled by a body falling freely from rest in second , third and fifth second of its motion are in what ratio? please explain step by step.
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in 1st sec.=1/2×gt²
1/2×9.8×1²
=4.9m
in 3rd sec.=1/2×9.8×3×3
=44.1m
in 5th sec.=1/2×9.8×5×5=122.5
in ratio =4.9:44.1:122.5
=49:441:1225
1/2×9.8×1²
=4.9m
in 3rd sec.=1/2×9.8×3×3
=44.1m
in 5th sec.=1/2×9.8×5×5=122.5
in ratio =4.9:44.1:122.5
=49:441:1225
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