Physics, asked by rupu48, 11 months ago

the distance travelled by a body falling freely from rest in 2 second 3 second and fifth second of its motion are in the ratio

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Answered by nikhil497146
4

s(2) = g(2 -  \frac{1}{2})
s(2) = 15 -----------(1)

s(3) = g(3 -  \frac{1}{2}) = 25 -  -  -  -  -  -  -  -  -  -  -  -  - (2)
s(5) = g(5 -  \frac{1}{2}) = 45  -  -  -  -  -  -  -  -  -  -  -  -  - (3)
s(2) : s(3) : s(5) = 15:25:45 = 3:5:9
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