Question

The distance travelled by a body in 4 th sec. is 24 m and in 6th sec. is 36 m . Calculate the velocity attained by a body at the end of 3 sec.​

Answer 1

Answer:

Correct option is

A

4.9m

Let the horizontal distance be H and  

let the distance traveled in the last second be d

H=  

2g

u  

2

 

​

 

H=  

19.6

1600

​

 

H=81.63m

Now time taken by the body to reach a height of 81.36 m=  

g

2H

​

 

​

=4.08s

Now from equation of motion, we have

s=ut+  

2

1

​

gt  

2

 

H−d=(40)(t−1)−  

2

1

​

g(t−1)  

2

 

81.63−d=(40)(4.08−1)−  

2

1

​

(9.8)(4.08−1)  

2

 

d=4.85m

So, the correct answer is '4.9m'.

Answer 2

Answer:

1 is your answer ,,