The distance travelled by a body in fourth second of a journey is twise the distance travelled in first second if the acceleration is 3m/s^2.then find initial velocity of the body
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s
4
=2s
2
(4u+
2
a
4
2
)−(3u+
2
a
3
2
)=2{(2u+
2
a
2
2
)−(u+
2
a
}
⇒10.5−9=u
⇒u=
2
3
m/s
give me some multiple thanks
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