Physics, asked by madalaharshitha, 1 month ago

The distance travelled by a body in fourth second of a journey is twise the distance travelled in first second if the acceleration is 3m/s^2.then find initial velocity of the body​

Answers

Answered by s1274himendu3564
0

s

4

=2s

2

(4u+

2

a

4

2

)−(3u+

2

a

3

2

)=2{(2u+

2

a

2

2

)−(u+

2

a

}

⇒10.5−9=u

⇒u=

2

3

m/s

give me some multiple thanks

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