Question

The distance travelled by a body in the 4th second is twice the distance travelled in the 2nd second. If the acceleration of the body is 3 m/s² then its initial velocity is___
a)3/2 m/s¹
b)5/2 m/s¹
c)7/2 m/s¹
d)9/2 m/s¹​

Answer 1

Answer:

The correct option is a) 3/2 m/s^1

Solution :-

s4 = 2s2

$(4u + \frac{a}{2} {4}^{2} ) - (3u + \frac{a}{2} {3}^{2} ) = 2 \: (2u + \frac{a}{2} {2}^{2} ) - (u + \frac{a}{2} )$

$= > \: 10.5 - 9 = u$

$u = \frac{3}{2} \: m/s$

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