Physics, asked by madhurayadiyal210, 2 months ago

The distance travelled by a body is (20.0+ 0.1) m in (5.0+ 0.1) s. The average speed of body with absolute error
(4.0 +0.2) m/s
(4.0 + 0.1) m/s
(4.0 +0.0) m/s
(4.0 + 0.01) m/s​

Answers

Answered by mantriavani5
8

Answer:

(4.0 + 0.0) m/s

Explanation:

Speed = Distance/Time

(20.0 +0.1) = 20.1

(5.0 + 0.1) = 5.1

Speed = 20.1 /5.1

= 4.0

So, the answer is (4.0 + 0.0)m/s

Answered by amitnrw
3

Given :  The distance travelled by a body is (20.0± 0.1) m   in (5.0± 0.1) s.

To Find : The average speed of body with absolute error

(4.0 +0.2) m/s

(4.0 + 0.1) m/s

(4.0 +0.0) m/s

(4.0 + 0.01) m/s​

Solution:

Distance = Speed * Time

Speed = s

Distance = d

Time = t

s  = dt

s  + Δs/s  =   d/t  + Δd/d  + Δt/t

d/t   = 20/5  = 4  m /s

Δd/d  = 0.1/20  =  1/200

Δt/t =   0.1/5  = 1/50

Δs/s  = 1/200 + 1/50

=> Δs/4  =  5/200

=> Δs = 5/50

=> Δs =1/10

=> Δs = 0.1

s  + Δs   = 4 ± 0.1  m/s

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