The distance travelled by a body is (20.0+ 0.1) m in (5.0+ 0.1) s. The average speed of body with absolute error
(4.0 +0.2) m/s
(4.0 + 0.1) m/s
(4.0 +0.0) m/s
(4.0 + 0.01) m/s
Answers
Answer:
(4.0 + 0.0) m/s
Explanation:
Speed = Distance/Time
(20.0 +0.1) = 20.1
(5.0 + 0.1) = 5.1
Speed = 20.1 /5.1
= 4.0
So, the answer is (4.0 + 0.0)m/s
Given : The distance travelled by a body is (20.0± 0.1) m in (5.0± 0.1) s.
To Find : The average speed of body with absolute error
(4.0 +0.2) m/s
(4.0 + 0.1) m/s
(4.0 +0.0) m/s
(4.0 + 0.01) m/s
Solution:
Distance = Speed * Time
Speed = s
Distance = d
Time = t
s = dt
s + Δs/s = d/t + Δd/d + Δt/t
d/t = 20/5 = 4 m /s
Δd/d = 0.1/20 = 1/200
Δt/t = 0.1/5 = 1/50
Δs/s = 1/200 + 1/50
=> Δs/4 = 5/200
=> Δs = 5/50
=> Δs =1/10
=> Δs = 0.1
s + Δs = 4 ± 0.1 m/s
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