Question

The distance travelled by a car which is initially at rest, moves with an acceleration 5 m/s² for 5 s is Pls answer i'll mark as brainliest

Answer 1

Answer:

Distance (s) = 62.5

Explanation:

Given that

a = 5 m/s²

t = 5 s

u = 0 [ as the car is initially at rest ]

Formula

s = ut + (1/2) at². [2nd equation of motion]

Placing the values

s = (0x5) + (1/2)(5)(5²)

= 0 + (125/2)

= 62.5

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