Question

the distance travelled by a freely falling body in 6 sec​

Answer 1

Answer:

using formula s=ut+1/2at^2. here u is 0 because in dropped case u is always0. and ais equal to g=10. so s=1/2×10×36= 180m distance

Answer 2

Answer:

If Friction is avoided then equation :-

here s=displacement(?)

u=initial speed(0)

t=time(6)

a= acceleration(9.8)

s=ut+0.5×at^2

s=0×6×0.5×9.8×6^2

s=0+176.4

s=176.4 ( approx)

Explanation:

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