Question

. The distance travelled by a freely falling body in one second, two second, three second etc are in the ratio

A) 1 : 1 : 1 B) 1 : 2 : 3 C) 1 : 3 : 5 D) 1 : 4 : 9​

Answer 1

Answer

here full proof -

Distance covered in tth second,  St=u+1/2g(2t−1)

∴  St=0+1/2g(2t−1)=21g(2t−1)

Distance travelled in first second i.e. t=1,  S1=1/2g(2×1−1)=1/2g

Distance travelled in 2nd second i.e. t=2,  S2=1/2g(2×2−1)=3/2g

Distance travelled in third second i.e. t=3,  S3=1/2g(2×3−1)=5/2g

⟹  S1:S2:S3=1:3:5