Question

The distance travelled by a particle moving along a straight line is given by x= 4t+5t2 +63
meter. Find a) the initial velocity of the particle b) the velocity at the end of 4 s
c) the
acceleration of the particle at the end of 5 s.​

Answer 1

Answer:

velocity, <br>

<br>

<br> (ii) Velocity of the particle when

<br>

<br>

<br> (iii) Accelration, <br>

= 0 + 10 + 36 t =10 36 t

t=5 s