Physics, asked by lokeshrocky, 1 year ago


The distance travelled by a particle
starting from rest and moving with an
acceleration 4/3ms-2 in the third second is

Answers

Answered by deepak344350
6

Answer:

3.3mt (n= 3)

sn = u + a/2 (2n-1)

u= 0 starting from rest

sn = 4/3*2 (2*3-1)=10/3=3.3 mt

Similar questions