The distance travelled by a particle starting from rest and moving with an acceleration 43ms−2, in the third second is :
Answers
Answered by
7
Distance travelled in 3 second
S = ut+(1/2)at²
S = (0xt) + (1/2)43(3²)
S = 387/2 m
Distance travelled in 4 second
S = ut+(1/2)at²
S = (0xt) +(1/2)43(4²)
So, distance travelled in 3rd second
= (43x4²)/2 - (43x3²)/2
=43(4²-3²)/2
=43(16-9)/2
=(43x7)/2
=301/2
=150.5 m
S = ut+(1/2)at²
S = (0xt) + (1/2)43(3²)
S = 387/2 m
Distance travelled in 4 second
S = ut+(1/2)at²
S = (0xt) +(1/2)43(4²)
So, distance travelled in 3rd second
= (43x4²)/2 - (43x3²)/2
=43(4²-3²)/2
=43(16-9)/2
=(43x7)/2
=301/2
=150.5 m
Similar questions