Question

The distance travelled by a particle starting from rest and moving with an accleration 4/3 ms-2,in the third second???​

Answer 1

Answer:

Distance covered in nth second,

S

n

=u+

2

1

a(2n−1);

=0+

2

1

×

3

4

(2×3−1)

=

2

1

×

3

4

×5=

3

10

m

Answer 2

Answer:

u=0

a=4/3

t=3 second

by second equation

s=ut+1/2 at²

s=0×3+1/2×4/3×3×3

s=2/3×9

s=6