Question

the distance travelled by a taxi (in km)for five riders are give below:15,17,20,22 find the mean distance travelled​

Answer 1

Answer:

255

Step-by-step explanation:

Correct option is

A

Fixed charge is Rs.5 and the charge per kilometer is Rs.10 For 25 km person have to pay Rs.255.

Let fixed charge be Rs x and charge per km be Rs y.

⇒x+10y=105...(1)

⇒x+15y=155..(2).

Now From eq 2

⇒15y=155−x5

⇒y=

15

155−x

...(3)

Substituting y from eq3 in eq1

⇒x+

15

10(155−x)

=105

⇒15x+1550−10x=1575

⇒5x=1575−1550

⇒5x=25

⇒x=5

Substituting x in eq2

⇒5+15y=155

⇒15y=155−5

⇒15y=150

⇒y=10

Hence x=5 and y=10

Fixed charge is Rs.55 and the charge per kilometer is Rs.1010

For 2525 km person have to pay = 5+10×25=255Rs.

Answer verified by Toppr

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