The distance travelled by a train is 1830 km. The speed of the train is one more than twice the time taken to travel the distance. What will be the respective ratio of the time taken and speed of train?
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Distance (D) = Speed (S) * Time (T)
Speed is 1 more than 2T. So, S = 1 + 2T
1830 = (1 + 2T) * T
2T² + T = 1830
2T² + T -1830 = 0
2T² - 60 T + 61 T - 1830 = 0
2 T (T - 30) + 61 (T - 30) = 0
(2T + 61) + (T - 30) = 0
T = -61/2 or 30
-61/2 is rejected because T can not be -ve.
So, T = 30 hours
Speed = 1 + 2 T = 1 + 2(30) = 61 km/h
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