Question

The distance travelled by an object is given by x=at+[bt^2/(c+a)] where t is time a,b,c are constants . The dimensions of b and c are



[LT^-2] , [LT^-1]

[L^2T^-3] , [LT^-1]

[LT^-1] , [L^2T^-1]

[LT^-1] , [LT^-2]

​

Answer 1

Answer:

option a

Explanation:

b=LT^-2 c= LT^-1