Question

The distance travelled by an object is given by x = at +bt²/(c+a)
where t is time and a, b, c are constants. The dimensions of b and c respectively are
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Answer 1

Explanation:

The answer is LT-³ ..

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Answer 2

$x=a+bt+ct^2$

$L^1=a$

$L^1=bt$

$b=L^1t^{-1}$

$cT^2=L\Rightarrowc=L^1^{-2}$

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