Question

The distance travelled by particle in time t given by s=2.5t.² find the average speed of particle during the time is o to 5sec.
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Answer 1

Answer:

12.5m/s

Explanation:

Expression for velocity:

     v=dtds

     v=dtd(2.5m/s2)t2

     v=(5m/s2)t

Average speed from 0 to 5 sec

      Distance travelled during 0 to 5 sec=(2.5m/s2)t2=(2.5m/s2)(5s)2=62.5m

      Average speed:

      v=totaltimetotaldistancetravelled

      v=562.5

      v=12.5m/s