The distance travelled by the body as per given velocitytime in the graph is
(A) 200 m
(B) 250 m
(C) 300 m
(D) 400 m
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Hey friend here's your ans hope it helps .....
Please mark as brainest if it helps......
Please mark as brainest if it helps......
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this figure is the trapezium so the distance is 1/2×height(sum of parallel side)
so distance is= 1/2×10(10+30)
=5(40)
=200m
so distance is= 1/2×10(10+30)
=5(40)
=200m
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