Physics, asked by panshul26, 1 day ago

the distance travelled s(in cm) by a particle in t seconds is given be s=t³+2r²+t. the speed of particle after 1 sec will be​

Answers

Answered by ELCTARJIT77
1

Answer:

s=t

3

−3t

2

∴ Velocity v=

dt

ds

=3t

2

−6t

and acceleration =

dt

dv

=6t−6=0 (given) ⇒t=1

Hence required velocity =v∣

t=1

=3−6=−3 m/s

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