the distance travelled s(in cm) by a particle in t seconds is given be s=t³+2r²+t. the speed of particle after 1 sec will be
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Answer:
s=t
3
−3t
2
∴ Velocity v=
dt
ds
=3t
2
−6t
and acceleration =
dt
dv
=6t−6=0 (given) ⇒t=1
Hence required velocity =v∣
t=1
=3−6=−3 m/s
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