Physics, asked by hmod22, 8 months ago

The distance (x) in meters travelled by a particle is related to time (t) in seconds by the equation of motion x = 10t + 4t2. What is the initial velocity of the body?

Answers

Answered by Anonymous
11

V = 10 + 8t

at t = 0

initial velocity,

v = 10m/s Ans

Answered by bhuvna789456
7

Initial velocity of the body is 10 m s⁻¹

Explanation:

  • Velocity of any body is defined as rate of change of displacement. It is a vector quantity that is have direction as well as magnitude.
  • Instantaneous velocity is the velocity at any given instant and we can calculate it by differenciating the displacement equation and then substitute the time given

Given, equation of motion is x = 10 t + 4 t²

by diffenciating the given equation velocity = \frac{dx}{dt}

=> velocity = \frac{d(10t+4t^{2} }{dt}

=> velocity = 10 +8 t

at initial point t= 0

=> velocity = 10 m s⁻¹

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