Question

The distance x of a particle in time t given by 10t^2-4t-x=0.where x is in metre and t in second. The distance covered by the body in 4th second of motion.​

Answer 1

Answer:

Since, t=4second given so

Put the value of t=4in the given equation and find that 

The value of x=144

10*4*4-4*4-x=0

160-16-x=0

X=160-16

X=144

Explanation:

We know that the for 4th second there we use formulae of s4th - s3rd and that is 

We put the value of t =4 in given equation and t=3in given equation and subtract the value of S3 from S4

Then

10*4*4-4*4-x=0

X=144 it is the value of S4

Now, 10*3*3-3*3-x=0

X=78

So, the final answer is 144-78=66

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